A. dividing the total longitudinal moment summation by displacement
B.dividing the total vertical moment summation by displacement
C.multiplying the MT1 by the longitudinal moments
D.subtracting LCF from LCB
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A.metacentric height
B.mean draft
C.moment to trim one inch
D.deadweight
A.lower than the center of gravity
B.at the same height as the center of gravity
C.higher than the baseline
D.on the longitudinal centerline
A.free surface effects are reduced due to pocketing
B.KG is reduced as the vessel seeks the angle of loll
C.effective beam is increased causing BM to increase
D.underwater volume of the hull is increased
A.vertically above the center of buoyancy
B.vertically above the center of gravity
C.at the intersection of the upright vertical centerline and the line of action of the buoyant force
D.at the geometric center of the underwater volume
A.The foot／tons needed to trim the vessel by 1 inch
B.The foot／tons needed to trim the vessel by 1 foot
C.The moments needed to trim the vessel by 1 centimeter
D.The amount of vessel will trim when loading 100 tons 100 feet from the tipping Center
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（）refers to the tendency of a body of the ship to return to its original position after it is displaced therefrom.
A vessel with a large GM will（）.
What is MTI?（）.
For small angles of inclination，if the KG were equal to the KM，then the vessel would have（）.
At all angles of inclination，the metacenter is（）.
If the cause of severe list or trim is off-center ballast，counterflooding into empty tanks will（）.
For a given displacement，the righting arm has its maximum value when（）.
A vessel’s KG is determined by（）.
A partially full tank causes a virtual rise in the height of the（）.
A vessel trimmed by the stern has a（）.