閱讀下面的程序,回答問題
DATA SEGMENT
BUF DB '1234'
N=$-BUF
BCD DB N DUP(?)
DATA ENDS
CODE SEGMENT
ASSUME CS:CODE,DS:DATA
START:MOV AX,DATA
MOV DS,AX
LEA SI,BUF
MOV CX,N
LEA DI,BCD+N-1
LOOP1:MOV AL,[SI]
SUB AL,30H
MOV [DI],AL
INC SI
DEC DI
DEC CX
JNE LOOP1
MOV AH,4CH
INT 21H
CODE ENDS
END START
閱讀下面的程序,回答問題
DATA SEGMENT
BUF DB '1234'
N=$-BUF
BCD DB N DUP(?)
DATA ENDS
CODE SEGMENT
ASSUME CS:CODE,DS:DATA
START:MOV AX,DATA
MOV DS,AX
LEA SI,BUF
MOV CX,N
LEA DI,BCD+N-1
LOOP1:MOV AL,[SI]
SUB AL,30H
MOV [DI],AL
INC SI
DEC DI
DEC CX
JNE LOOP1
MOV AH,4CH
INT 21H
CODE ENDS
END START
程序執(zhí)行后,從BCD開始的N個字節(jié)單元中的內(nèi)容是1234。