A.CH$′123450′ B.AT(CH,′12345′)=0 C.′123450′$CH D.′123450′=CH
A.trim(a)+b+space(len(a)-len(trim(a))) B.trim(a)=b C.a+b D.a*b
A.8/27/65 B.出錯(cuò) C.12/23/65 D.12/27/61